Cite. 195 2 2 silver badges 6 6 bronze badges $\endgroup$ 4 $\begingroup$ i have seen answer to this question as 101/125 in another website, but i think that is wrong $\endgroup$ - Chaos. Considering two situations: 1) the player is smart enough that he will do "bisection" based on the feedback (first . Human brains are terrible at picking random numbers. So, to figure out your odds of winning, multiply together all of the fractional odds of picking a given number correctly, as stated by the red fractions above. 9 is too close to the end and 7 seems . So, at this point, your odds of winning are 1 in 20274183401472000 . Hence, to get any number between $1$ and $100$, all you need to know are its $7$ digits in binary. The general formula is given as P(A chooses the same number as B)=sum P(A chooses number i)*P(B chooses number i) due to independence. A 1 in 500 chance of winning, or probability of winning, is entered into this calculator as "1 to 500 Odds are for winning". Irrespective . All of your answers should be between 0 and 1. If I ask you to pick out one ball at random, the probability of choosing a red ball would be 1 in 3. Odd / Even ×. In this exact order. A player must choose 5 numbers between 1 and 69 and 1 Powerball number between 1 and 26. 1/10 000. etc but only 100 possible outcomes where these match (1,1), (2,2), ., (100,100) so you work out the probability of picking the same number by: number of outcomes where they match . Just to add some clarifications. But, since you can choose your winning numbers in any order, your chances of winning . Aug 4 '15 at 21:53. Cite. Third person will have 2 k probability. n -th person will have n − 1 k probability. 1/20 × 1/19 × 1/18 × 1/17 × 1/16 × 1/15 × 1/14 × 1/13 × 1/12 × 1/11 × 1/10 × 1/9 × 1/8 × 1/7 × 1/6 = 1/20274183401472000 So, at this point, your odds of winning are 1 in 20274183401472000. 2/10 000. If n is odd and x is anything but n/2 rounded up, you own them. Last I checked. So that is effectively a 5 number selection from 69 numbers and a 1 number selection from 1 to 26. Suppose we have 6 chances to guess a random number between 1 and 100, then it's obvious that the probability of getting the correct answer is $\frac{6}{100}$. (b) The probability that both persons pick the same number is: 2/100. The chosen number must be in between 1 to 5 (including 1 and 5). Aug 4 '15 at 21:53. If you were to answer 1 or 10, it is as if you're avoiding answering the question, and kind of mocking the questioner. Tell a girl pick a number and I will guess it. You can determine a specific range of numbers or you can use one of the several set number generators. There you can put any random number distribution (as long as it is discrete, as for continuous the probability is zero . AC0, F00, CCC) Find a random hex color here. But, since you can choose your winning numbers in any order, your chances of winning are . To calculate the odds, we need to work out the number of combinations, not permutations, since it doesn't matter what way the numbers are arranged to win. 100, 200, 500) Font color in hex (e.g. Each number would have a 10% chance of being chosen and even and odd numbers would be chosen 50% of the time. Add magic filter add_circle_outline. Human brains are terrible at picking random numbers. $100$ in binary is $1100100$. Odd / Even ×. Tell her again, pick another number > She will think about 5 and then 3. Answer (1 of 8): Assume that the numbers in question are restricted to integers. Add/Roll Dice ×. Question 2: this answer is just 1. 100, 200, 500) Font color in hex (e.g. The odds are 1/10. So you ask the question if the first digit is $0$. For the normal answer, people have done surveys on this. 1/200. There are k choices and n people. First person will choose a random number. The answer posted by Jorge is right. Here are the results of a couple I've come across: SOURCE: Asking over 8500 students to pick a random number from 1 to 10 [OC] SOURCE: Responses when people were asked for. OK. Statistics ×. Your colleague is correct. probability. If they weren't, when asked a question like this, there would be an even distribution of answers between 1 and 10. 1/10 000. Also, 5 is exactly in the middle. But, since you can choose your winning numbers in any order, your chances of winning are . Share. I don't necessarily need an answer as that was just an example, rather I am looking for . If the probability density functions P_1 and P_2 are in som. 1/100. "And part of those conditions was the meaning of . If I've chosen a number between 1 and 10 and ask you to guess, randomness is only associated with your guess. you guess the first one wrong) is . However, the probability that you are going to make the second guess (i.e. 1 / 20 × 1 / 19 × 1 / 18 × 1 / 17 × 1 / 16 × 1 / 15 × 1 / 14 × 1 / 13 × 1 / 12 × 1 / 11 × 1 / 10 × 1 / 9 × 1 / 8 × 1 / 7 × 1 / 6 = 1 / 20274183401472000. But there are 10,000 possible outcomes of possible pairs of numbers you could both pick (1,1), (1,2), (1,3), . Use the start/stop to achieve true randomness and add the luck factor. A formula for calculating probability from odds is P = O / (O + 1). So, at this point, your odds of winning are 1 in 144978876000. Font size in pixels (e.g. So you ask the question if the first digit is $0$. probability. Irrespective . OK. Statistics ×. 1/100. 6.3 is between 1-10. It is always true, when picking three numbers, that 3 numbers are picked in some order. Display Font ×. The odds of choosing the same number are 1:99. Once done, click the "Generate Random Numbers" button and they will instantly appear. When people are asked to pick a number between 1 and 10 the most common number that people pick is 7 because it seems 'the most obscure'. The answer is the total number of outcomes. But there are 10,000 possible outcomes of possible pairs of numbers you could both pick (1,1), (1,2), (1,3), . It is always true, when picking three numbers, that 3 numbers are picked in some order. 2/10 000. Display Font ×. 7y People are actually fairly reasonable random digit generators. Probability can be expressed as 9/30 = 3/10 = 30% - the number of favorable outcomes over the number of total possible outcomes. There's a difference between probability and odds. So, at this point, your odds of winning are 1 in 144978876000. The way I read the question is that both people randomly choose at the same time, of which there are 100 possibilities and only one way for them to be the same. Now suppose that after each guess the player can obtain a feedback telling him whether the guess is too low or too high. So that is effectively a 5 number selection from 69 numbers and a 1 number selection from 1 to 26. Meanwhile the chance of the other person picking that exact number is 1/10. 1 / 50 × 1 / 49 × 1 / 48 × 1 / 47 × 1 / 46 × 1 / 45 × 1 / 44 = 1 / 503417376000. Lets you pick a number between 1 and 10. Your opponent chooses a number, x. But that's not what happens. I'm not sure I agree. Question 2: this answer is just 1. The question is: Suppose two people each have to select a number from 00 to 99 (therefore 100 possible choices). On the second guess, your chance increases to $\frac 1 {99}$ as you know the answer isn't your guess and you aren't going to make the same guess. Note that all positive integers between $1$ and $100$, when represented in binary has at most $7$ digits. When people are asked to pick a number between 1 and 10 the most common number that people pick is 7 because it seems 'the most obscure'. The answer is the total number of outcomes. The chosen number must be in between 1 to 5 (including 1 and 5). 1 $\begingroup$ $\frac{1}{125}$. The question is: Suppose two people each have to select a number from 00 to 99 (therefore 100 possible choices). Question 1: there are 10 c 3 ways of picking three distinct numbers, but what is the probability? Hence, to get any number between $1$ and $100$, all you need to know are its $7$ digits in binary. So, to figure out your odds of winning, multiply together all of the fractional odds of picking a given number correctly, as stated by the red fractions above. Chaos Chaos. You may also see odds reported simply as chance of winning as 500:1. Games Lotto Number Generator Lottery Numbers - Quick Picks Lottery Number Scrambler UK49 Lucky Pick Odds of Winning Flip a Coin Roll a Die Roll a D20. This is due to the fact that $2^7 = 128 > 100$. $100$ in binary is $1100100$. Magic Filters × . 4 . Answer (1 of 17): There's a normal answer, and a smart ass answer. A probability is a number between 0 and 1. Random Numbers Combination Generator Number Generator 1-10 Number Generator 1-100 Number Generator 4-digit Number Generator 6-digit Number List Randomizer Popular Random Number Generators. Odds of picking the same number. So, to figure out your odds of winning, multiply together all of the fractional odds of picking a given number correctly, as stated by the red fractions above. I'll repeat what I said: I'm picking a number between 1-10. Follow asked Aug 4 '15 at 21:51. A formula for calculating probability from odds is P = O / (O + 1). (a) The probability that they both pick the number 13 is: 2/100. This most likely means "500 to 1 Odds are against winning" which is exactly the same as "1 to 500 Odds are for winning." Probability Formulas: This calculator will convert "odds of winning" for an event . Thus rhe chance of said effect happen is given as 1*1/10=1/10. There's a difference between probability and odds. 4 . 195 2 2 silver badges 6 6 bronze badges $\endgroup$ 4 $\begingroup$ i have seen answer to this question as 101/125 in another website, but i think that is wrong $\endgroup$ - Chaos. Probability can be expressed as 9/30 = 3/10 = 30% - the number of favorable outcomes over the number of total possible outcomes. Use the start/stop to achieve true randomness and add the luck factor. Thus, if you picked a 4-digit number randomly, you'd have a one in 10,000 chance of picking that number (or any other specific 4-digit number). A simple formula for calculating odds from probability is O = P / (1 - P). Share. Now, if I added another green ball so that there are now 2 green balls in the bag, the probability of picking out a red ball has dropped to 1 in 4. So, to figure out your odds of winning, multiply together all of the fractional odds of picking a given number correctly, as stated by the red fractions above. A player must choose 5 numbers between 1 and 69 and 1 Powerball number between 1 and 26. There you can put any random number distribution (as long as it is discrete, as for continuous the probability is zero . 1/200. Add/Roll Dice ×. The second man will pick integer i in the same range with probability P_2(i). Magic Filters × . Viewed 8k times 2 1 $\begingroup$ I'm trying to figure out how to calculate this: If 3 people have to pick a number between 1 and 9. whats the probability of 1 or more of them picking the same number? 1 / 75 × 1 / 74 × 1 / 73 × 1 / 72 × 1 / 71 × 1 / 70 = 1 / 144978876000. So, to figure out your odds of winning, multiply together all of the fractional odds of picking a given number correctly, as stated by the red fractions above. Lets you pick a number between 1 and 10. OK. Custom Enter number of odd numbers. OK. If "between 1 Continue Reading Related Answer Quora User , I'm an Aussie feller, I've been one all my life. (b) The probability that both persons pick the same number is: 2/100. The first person has . If you are asked to pick a number between 1 and 10, there is an implicit implication that it should be a "random" number in that range, and not a "special" number. That only leaves 3, 7 and 9. The odds of choosing the same number are 1:99. Think of it this way: there are 10,000 ($10^4$) 4-digit numbers: 0000-9999.Your target number is one of those 10,000. You didn't get it, and you got the probability wrong, too. Second person will choose a random number and will have 1 k probability to choose the number chosen by others. Note that all positive integers between $1$ and $100$, when represented in binary has at most $7$ digits. Chaos Chaos. etc but only 100 possible outcomes where these match (1,1), (2,2), ., (100,100) so you work out the probability of picking the same number by: number of outcomes where they match . (a) The probability that they both pick the number 13 is: 2/100. The first person has . Active 6 years, 3 months ago. Thus rhe chance of said effect happen is given as 1*1/10=1/10. 1 / 75 × 1 / 74 × 1 / 73 × 1 / 72 × 1 / 71 × 1 / 70 = 1 / 144978876000. If n is odd and they choose n/2 rounded up, you should have gone first. People will stay away from 1 and 10 because they are too extreme, all the even numbers have too much of a recognisable pattern and 5 is too obvious because of its position in the middle. If "between 1 and 10" is exclusive (can't pick 1 or 10) then the chance is 100% that at least two people will pick the same number, because of the pigeonhole principle: 10 people can pick among 8 numbers, so some will need to share. If they weren't, when asked a question like this, there would be an even distribution of answers between 1 and 10. Meanwhile the chance of the other person picking that exact number is 1/10. If n is even and x is anything but n/2 or n/2+1 (5 or 6 for "pick a number between 1 and 10"), you own them. If you were to answer 1 or 10, it is as if you're avoiding answering the question, and kind of mocking the questio. Geting the probability that way will be way too hard, let's get the . Author has 108 answers and 95.1K answer views The numbers people choose if you tell them to pick a number between 1 and 10 are the following: 7 > 5 > 3. A 1 in 500 chance of winning, or probability of winning, is entered into this calculator as "1 to 500 Odds are for winning". In the first try you have $\frac 1 {100}$ chance of guessing it right. Custom Enter number of odd numbers. First, pick the number of random numbers you need to be generated, then choose the number range you'd like the random number to be generated between. This exact same idea applies to all the . 1 $\begingroup$ $\frac{1}{125}$. She will pick 7. "I see what you did there. AC0, F00, CCC) Find a random hex color here. A probability is a number between 0 and 1. A simple formula for calculating odds from probability is O = P / (1 - P). The first man will pick integer i between 1 and 10 with probability P_1(i). Question 1: there are 10 c 3 ways of picking three distinct numbers, but what is the probability? Answer (1 of 17): If you are asked to pick a number between 1 and 10, there is an implicit implication that it should be a "random" number in that range, and not a "special" number. Ask Question Asked 7 years, 10 months ago. Font size in pixels (e.g. These include random numbers between 1 and 10, random . People will stay away from 1 and 10 because they are too extreme, all the even numbers have too much of a recognisable pattern and 5 is too obvious because of its position in the middle. Follow asked Aug 4 '15 at 21:51. So, at this point, your odds of winning are 1 in 503417376000. The general formula is given as P(A chooses the same number as B)=sum P(A chooses number i)*P(B chooses number i) due to independence. Number Converters Number Converter Hex Converter Decimal . Each number would have a 10% chance of being chosen and even and odd numbers would be chosen 50% of the time. Done. You're trying to say that all probability is conditional, and if you don't specify the conditions, you can't have a probability." That's right. To give a simplified example, lets say I have a bag with 1 red, 1 black and 1 green ball in it. All of your answers should be between 0 and 1. Done. This is due to the fact that $2^7 = 128 > 100$. If your number was 3 or 7, you're in the majority. This most likely means "500 to 1 Odds are against winning" which is exactly the same as "1 to 500 Odds are for winning." Probability Formulas: This calculator will convert "odds of winning" for an event . You may also see odds reported simply as chance of winning as 500:1. To calculate the odds, we need to work out the number of combinations, not permutations, since it doesn't matter what way the numbers are arranged to win. Add magic filter add_circle_outline. You choose a number, y.
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